Greetings to everyone today, Professor REYNER, everyone is welcome to our YouTube channel,
thanks to all those who have joined our hydraulics classes at this time
we are working on hydraulics I thank all those who leave me their comments and
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we all learn and seek knowledge for a much better life then
today's exercise is going to do an exercise number 2 is an application for a counter pressure valve
for a hydraulic foundation of double acting draw the diagram of a
double acting hydraulic cylinder with the following working conditions when giving a start signal to a
control valve 43 of this is going to be s 1 the rod of a cylinder moves out
with a speed controlled by pressure we have to give visualizations to the
pressures we have to control the pressures or measure the pressures s we have here that we are going
to turn off the valve 43 the rod of the hydraulic cylinder returns to its initial position
let's analyze the step and phase diagram and draw up the list of components that we have used from
the previous exercise I have left some things that will help me In order not to be copying them in
advance, we have the system pressure regulating valve, the shut-off valve and the
tank here, so now we are going to use a double-effect cylinder, we are going to take this one, which
is here, then we are also going to use a four-way valve. three positions that you
are asking us to use here then we come to make the connections of this valve we connect
here and this is this connection because in the socket that is going to go to the tank we come here we generate a
muscular effort of lever and return by action of a spring and We have our 43 valve now we are going
to locate here in the case of it it must come out with a regulated speed is what the problem is asking
us and It is also asking us to control or visualize more than anything to truly control
the pressures that are being generated in the system at the work exit at the
work exit see is where we normally need to control those pressures now we are going
to use the valve to regulate the pressure because we are going to use this pressure regulating valve
combined with a non-return valve that we find here where it says closing
and flow control bars we find this non-return valve that the one with the pellet and the one with the
spring, we will connect them in series of forgiveness in parallel between themselves in such a way
that we are going to find it like this in this way and we also need to locate a pressure gauge to
monitor the values ​​that are being generated in the output pressures of the connection to
work that in this case It would be the working connection then we are going to put the pressure gauge in
this position we are going to see I think that here I think they take from quite reliable way of use
and well we are going to lower it a little more because I see that this can in the simulation I think that there
is well here in the simulation in the pressure regulating or limiting valve it appears in
range 5 we are going to lower it to 2 for You see, well here we can regulate the expression by
limiting the pressure between different magnitudes in this case mega pascal in bars and psi in a
general way it comes in mega pascal is that it is equivalent to approximately 2 - fiscal at 20 20 bars well
we accept we are going to start right now there are no errors in the graph it means that everything is fine
and I have come to start a previous simulation when we press the exit logically that if I shout the
pulse signal and the plunger goes in 50 percent of its displacement when removing the signal him even if he
goes to the middle he is going to return then we can observe the speeds as we can see there goes
a speed and returns let's say practically the same speed we are going to look for the The diagram
has been in phase that is asking us so that we can control the speed of the cylinder, we are going
to control the different parameters, we are going to parameterize here and well, we will not need to
control these situations, so as we can see here, we are going to leave it this way,
press gear, let's see. the displacement and the speed now we are going to change it here we are going to
put it 5 6 7 8 bars omega pascale because here they are pascal that is when we start,
look that now it comes out much slower than the speed with which the displacement returns in
the speed here is different because the curve the speed curve starts a little high and to see
the longest displacement in the curve here is a little high from the one with the same displacement in
the speed since in the exit because he leaves much slower at the speed that he leaves that
is because when he leaves as we can see here the in this in this part of here the oil
is limited here and When he wants to find this other outlet, the valve and pellet that has this
valve, as we can see, we are going to use this simulation when we come here, we apply
the pressure to this valve with a lot of deposition and it allows the pressure vessel to the tank and
it is limited because there is a regulation but the oil pressure wants to return here
the pellet birds the pellet blocks its passage and there is no passage so that way as we can see right
now when I release it because then the case is different but here I block the oil from passing
but it is A controlled oil and here is an oil that is blocked by the pellet, in this way,
the pressure of this system is being regulated.Now we are going to name the tank for this other one
, well, we do this for the purpose of the list of parts to appear. each and every one of
them there named in the case of these manometers here we have the manometer like the manometers here
there are several because we are going to name the manometer here So then here it is necessary to name it as
unit 0 and in fact we have to come to name all these here because it is already if there is
already a derivation that may tend to confuse then we have to determine that there is a single
motor generating unit that is only one pump but there are several manometers that is the only
thing with the zero manometer this would be manometer 1 and here we would have manometer 2 then in the
order from bottom to top and from left to right then this would be manometer 1 so
that they remain There named and in the valve we are going to put a name to this valve that
we have here this is the valve well they work with cylinder 1 therefore this is 1 b
0 because this is the first I will start from zero then this So here I don't get cylinder 1
and well, I already put one on it, this would be the valve,
we are going to put the m1
2 because here we already have 1 the 2 and here this would be the 3 we are going to work with
the cylinder 1 and it would be l to valve 3 in the order of the fractions that we come here, see here we already had the other one
here and we do not use it so here we already have the non-return valve we do not name them
excuse me in front of this one here then it would be the other valve and in this case it would be the 1 b
4 because this is the order that we are using so here we already have the whole list of the
elements that we are using in the component in the simulation diagram and well now so
right here I think the whole exercise is complete, we click on start it It comes out slowly when
we remove the pulse of the fast return in fact if we remove the regulation most of it because
at the moment of pressing the it comes out faster than we have it when what we put a regulation
if we put it we are going to put it 10 let's see If we have not limited in fact we have limited it so much
that there is no pass it does not allow us to pass then we are going to lower it to 8 we exceeded its capacity
without now if we see there with nothing now to Yes we can see that here we have this exercise already
solved. I thank everyone who has been watching these tutorials. We are going to continue working
to logically continue learning more in this case of the hydraulics simulation. Have
a good day, the teacher says goodbye to you. rainer and no luck at all